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LinuxGuy
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 Posted: Wed May 10, 2006 10:21 pm Post subject: Will this code leaks memory |
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Can someone please tell if following code leaks memory
void someFunction()
{
char MyArray[512];
memset(MyArray,0,512);
}
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Victor Bazarov
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| Posted: Thu May 11, 2006 6:21 pm Post subject: Re: Will this code leaks memory |
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LinuxGuy wrote:
| Quote: | Can someone please tell if following code leaks memory
void someFunction()
{
char MyArray[512];
memset(MyArray,0,512);
}
|
No, it doesn't seem to. An easier way to make the array 0 would be
to initialise it
char MyArray[512] = {0};
(yes, I know, the '0' in those curly braces is not necessary, I just
find it a bit more readable).
V
--
Please remove capital As from my address when replying by mail
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Jeffrey Schwab
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| Posted: Thu May 11, 2006 6:21 pm Post subject: Re: Will this code leaks memory |
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LinuxGuy wrote:
| Quote: | Can someone please tell if following code leaks memory
void someFunction()
{
char MyArray[512];
memset(MyArray,0,512);
}
|
It shouldn't, unless you're doing something funky elsewhere. I can't
say I like the hard-coded 512, though. Why would this be leaky?
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Eric
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| Posted: Thu May 11, 2006 10:21 pm Post subject: Re: Will this code leaks memory |
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LinuxGuy wrote:
| Quote: | Can someone please tell if following code leaks memory
void someFunction()
{
char MyArray[512];
memset(MyArray,0,512);
}
|
No it wont, why did you think it might?
Eric
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arunkg999
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| Posted: Thu May 11, 2006 10:21 pm Post subject: Re: Will this code leaks memory |
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| Quote: | void someFunction()
{
char MyArray[512];
memset(MyArray,0,512);
}
|
This piece of code wont leak memory.
what you have done is made an automatic array fo 512 char and then set
0 into it. Once you get out of the scope, MyArray will get destroyed
automatically. Hence no leaks
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Thomas Maeder
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| Posted: Fri May 12, 2006 12:21 am Post subject: Re: Will this code leaks memory |
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"LinuxGuy" <rahul.ruikar (AT) gmail (DOT) com> writes:
| Quote: | Can someone please tell if following code leaks memory
|
Why do you think that it does?
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