C++Talk.NET C++ language newsgroups   Archives   FAQ   Search   Memberlist   Usergroups   Register   Profile   Log in to check your private messages   Log in  why some operators cannot be overloaded          C++Talk.NET Forum Index -> C++ language (comp.lang.c++) View previous topic :: View next topic   Author Message Bangalore Guest Posted: Tue Jul 26, 2005 6:45 am    Post subject: why some operators cannot be overloaded Hi, Can anybody explain , why some operators(::, ., .*, sizeof,? cannot be overloaded in C++? Thanks Back to top benben Guest Posted: Tue Jul 26, 2005 7:31 am    Post subject: Re: why some operators cannot be overloaded Quote: Hi, Can anybody explain , why some operators(::, ., .*, sizeof,? cannot be overloaded in C++? Thanks http://www.research.att.com/~bs/bs_faq2.html#overload-dot Back to top Ian Guest Posted: Tue Jul 26, 2005 7:56 am    Post subject: Re: why some operators cannot be overloaded Bangalore wrote: Quote: Hi, Can anybody explain , why some operators(::, ., .*, sizeof,? cannot be overloaded in C++? Because it makes no sense to do so. Ian Back to top suresh Guest Posted: Wed Jul 27, 2005 2:10 pm    Post subject: Re: why some operators cannot be overloaded Besides the sense can there be any other reasons?? Suresh Back to top Fabio Fracassi Guest Posted: Wed Jul 27, 2005 3:31 pm    Post subject: Re: why some operators cannot be overloaded suresh wrote: Quote: Ian wrote: Because it makes no sense to do so. Ian well thats not entirely true. There are very good reasons to overload either operator. and operator.* which is why allowing it is seriously considered for the next version of C++ see: http://www.open-std.org/JTC1/SC22/WG21/docs/papers/2004/n1671.pdf It is usful to implement smart references or other forwarding handles. Quote: Besides the sense can there be any other reasons?? Suresh Well it is certainly a good policy not to allow things which make no sence. The problem with all operator overloads is that it might lead to confusion, if the overloaded operators work differently from the "normal" version. In the case of an overloaded operator. There is for example no obvious way to call member functions of the class which overloads the operator. If you are interested in why c++ is as it is, you probably want to read Design & Evolution of C++ by Bjarne Stroustrup. HTH Fabio Back to top Display posts from previous: All Posts1 Day7 Days2 Weeks1 Month3 Months6 Months1 Year Oldest FirstNewest First         C++Talk.NET Forum Index -> C++ language (comp.lang.c++) All times are GMT Page 1 of 1   Jump to: Select a forum C/C++----------------C LanguageC Language (Moderated)C++ Language (Moderated)C++ language (comp.lang.c++)C++ language, library and standards Non-English C/C++ Newsgroups----------------C++ (German)C++ (French)  You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum Powered by phpBB © 2001, 2006 phpBB Group SEO toolkit © 2004-2006 webmedic.