C++Talk.NET

tingjun.li@gmail.com · Guest

There is a demo program:
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const char* WS = " \t\n";
const int n_WS = strlen(WS);

char* s1 = "This sentence contains five words.";
char* s2 = "OneWord";

char* end1 = find_first_of(s1, s1 + strlen(s1), WS, WS + n_WS);

char* end2 = find_first_of(s2, s2 + strlen(s2), WS, WS + n_WS);

printf("First word of s1: %.*s", end1 - s1, s1);

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I don't know What does "%.*s" stand for? It seems printf("%d %s", num,
string) is mostly used..

Rolf Magnus · Guest

tingjun.li (AT) gmail (DOT) com wrote:

lyang2@cisco.com · Guest

for s type, the integer value after dot (.) in the format string mean
the maximum number of characters to be printed. So I think * mean all
the characters will be printed out until first null character is
encountered.

Regards.

Kandy
tingjun.li (AT) gmail (DOT) com wrote:

tingjun.li@gmail.com · Guest

Thank you very much for all of your replies.

Now I know the answer: Thanks!

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In a string, precision is the maximum number of bytes to be printed
from the string; in a 'br number, the precision is the number of digits
to be printed to the right of the decimal point in a floating point
value. width or precision may be specified as *, in which case the
value is read from the next argument, which must be an integer. For
example:

printf "%*.*d\n" 20 10 200

is equivalent to

printf "%20.10d\n" 200

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Christopher Benson-Manica 写道：