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iwongu · Guest

Hi,

I have a question about std::wcout and its underlying C functions.

According to C99, a stream have an orientation type that is one of
byte-oriented or wide-one, and it is determined by the first using C
function on that stream. And the specific orientation functions should
not be applied to the stream that have other orientation.

And, the follwing code is working; (gcc 3.4.3 in solaris 10 x86)

wcout << "abcd" << endl;
wcout << "한글efgh" << endl; // the first four bytes are Korean
// characters.
wcout << "ijkl" << endl;

The result is;

abcd
한글efgh
ijkl

But the following is not.

wcout << L"abcd" << endl;
wcout << L"한글efgh" << endl;
wcout << L"ijkl" << endl;

The result is;

abcd

All characters are not printed after I try to print Korean.

I assumed that wcout might use byte-function (not wide-) to print
narrow characters even though it is wide character string literal. So
the stdout had byte-orientation and the rest are not printed because
they are wide-oriented function. But this assumption can not explain
the
last line; L"ijkl".

I tried more code.

wcout << "abcd" << endl;
wcout << L"한글efgh" << endl;
wcout << "ijkl" << endl;

The result is;

abcd

:-|

wcout << "abcd" << endl;
wcout << L"한글efgh" << endl;
cout << "ijkl" << endl; // <-- changed to cout

The result is;

abcd
ijkl

Is this a bug in compiler? What's the standard-correct output for this?

Thanks in advance.

iwongu.