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2005 Guest
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Posted: Sat Oct 28, 2006 6:29 am Post subject: Two objects created in a Single class |
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Hi
I have a situation that I created two objects in a Single class, say
CAll All_A, All_B;
I can access the public functions within them without the "."
operation, say public function Display(), Term() ; inside Display(), I
can do Term() { not All_A.Term() } since they are member functions.
The issue is I have All_A & All_B - how do I differentiate them?
Am I supposed to do
All_B.Term() just to differentiate them?
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David Harmon Guest
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Posted: Sat Oct 28, 2006 7:31 am Post subject: Re: Two objects created in a Single class |
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On 27 Oct 2006 18:29:54 -0700 in comp.lang.c++, "2005"
<uws2003 (AT) yahoo (DOT) com> wrote,
| Quote: | Hi
I have a situation that I created two objects in a Single class, say
CAll All_A, All_B;
I can access the public functions within them without the "."
operation, say public function Display(), Term() ; inside Display(), I
can do Term() { not All_A.Term() } since they are member functions.
The issue is I have All_A & All_B - how do I differentiate them?
Am I supposed to do
All_B.Term() just to differentiate them?
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When you call Term() inside CAll::Display(), it is the same as
this->Term(). It is called as a member function of the same object.
So All_A.Display() will end up calling Term() upon All_A, and
ALL_B.Display() will end up calling Term() upon All_B.
As soon as you have three objects you had better start thinking
about std::vector<CAll>. |
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2005 Guest
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Posted: Sat Oct 28, 2006 7:42 am Post subject: Re: Two objects created in a Single class |
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David Harmon wrote:
| Quote: | On 27 Oct 2006 18:29:54 -0700 in comp.lang.c++, "2005"
uws2003 (AT) yahoo (DOT) com> wrote,
Hi
I have a situation that I created two objects in a Single class, say
CAll All_A, All_B;
I can access the public functions within them without the "."
operation, say public function Display(), Term() ; inside Display(), I
can do Term() { not All_A.Term() } since they are member functions.
The issue is I have All_A & All_B - how do I differentiate them?
Am I supposed to do
All_B.Term() just to differentiate them?
When you call Term() inside CAll::Display(), it is the same as
this->Term(). It is called as a member function of the same object.
So All_A.Display() will end up calling Term() upon All_A, and
ALL_B.Display() will end up calling Term() upon All_B.
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Am I right to assume that inside the member function, I call
ALL_B.Display() & All_A.Display() since there 2 objs ( and it would be
redundant if there are only one object ).
| Quote: |
As soon as you have three objects you had better start thinking
about std::vector<CAll>. |
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David Harmon Guest
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Posted: Sat Oct 28, 2006 9:10 am Post subject: Re: Two objects created in a Single class |
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On 27 Oct 2006 19:42:07 -0700 in comp.lang.c++, "2005"
<uws2003 (AT) yahoo (DOT) com> wrote,
| Quote: | When you call Term() inside CAll::Display(), it is the same as
this->Term(). It is called as a member function of the same object.
So All_A.Display() will end up calling Term() upon All_A, and
ALL_B.Display() will end up calling Term() upon All_B.
Am I right to assume that inside the member function, I call
ALL_B.Display() & All_A.Display() since there 2 objs
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I don't know; what are you trying to accomplish? I certainly don't
see any reason to call both of them from within some other member
function, but you might have a reason.
| Quote: | ( and it would be redundant if there are only one object ).
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No, with only one object you certainly cannot call functions of two
objects.
Post a small but complete compilable sample of the code you are
trying to use. |
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