C++Talk.NET

Torsten Robitzki · Guest

Hi,
recently I've bought the latest MS c++ compiler to see if my current fun
project would compile with an other compiler then g++. I got error
messages in the serialization support code for template functions that
should write other templates like std::pair<> of boost::shared_ptr<>.
I'm not sure if koenig lookup should bring up the operators name I'm
like to see into the scope of this functions. Here's a simple reproducer
and the error message:

#include <utility>

namespace ns2
{
class cl
{
public:
template <class A, class B>
cl& operator<<(const std::pair };
}
namespace ns1
{
class foo
{
};

ns2::cl& operator<<(ns2::cl&, const foo&);
}

namespace ns2
{

template cl& cl::operator<<(const std::pair {
return *this << t.first << t.second; // line 27
}
}

void f()
{
ns1::foo f;
ns2::cl c;
c<<(std::pair }

The error message (translated from german) :
$ cl /c /I"C:ProgrammeMicrosoft Visual Studio .NET 2003Vc7include"
test.cpp
Microsoft (R) 32-Bit C/C++-Standardcompiler Version 13.10.3077 f r 80x8
6
Copyright (C) Microsoft Corporation 1984-2002. Alle Rechte vorbehalten.

test.cpp
test.cpp(27) : error C2784: 'ns2::cl &ns2::cl::operator <<(const
std::pair
von 'const ns1::foo' can not be deduced
test.cpp(9): see declaration of 'ns2::cl::operator`<<''
test.cpp(35): instanciated from here 'ns2::cl
&ns2::cl::operator << with
[
Ty1=ns1::foo,
Ty2=ns1::foo
]
test.cpp(27) : error C2676: binary operator '<<': 'ns2::cl' does not
define this operator or a conversion in a manner allowed for this
operator type

I guess this is a bug with the MS compiler, but I'm not sure. The only
workaround I've found so far is to inject the n1 namespace into the
operator<<(std::pair<>) by a 'using namespace n1'.

Can someone confirm that this is a bug? Does someone have a better
workaround for my problem?

thanks in advanced
Torsten

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