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Mohanasundaram · Guest

Hi All,

I have the following question asked by my friend.

/*Copiled using C++ compiler*/
#include <stdio.h>

int main()
{
const int i = 10;
int *p = (int *)&i;
++(*p);
printf("%dn",i);
printf("%dn",*p);
return 0;
}

The output is
10
11

/*Copiled using C compiler*/
#include <stdio.h>

int main()
{
const int i = 10;
int *p = (int *)&i;
++(*p);
printf("%dn",i);
printf("%dn",*p);
return 0;
}

The output is
11
11

We tried this in VC++ 6.0, gcc and solaris native compiler. All the
compilers give the same answer. My friend says it is the expected
behaviour of the languages. Is it the standard behaviour of the
languages? Can anyone please explain? I don't have any clue about
this?

Regards,
Mohan.

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Douglas A. Gwyn · Guest

Mohanasundaram wrote: