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templated constanst

 
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Javier Loureiro
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PostPosted: Sat Jun 10, 2006 4:35 am    Post subject: templated constanst Reply with quote



how can I write this template without a static member?

-- header --

template <typename Scalar>
struct A
{
static Scalar MAX_VALUE;
};

-- explict instance --

A<float>::MAX_VALUE = FLT_MAX;
A<double>::MAX_VALUE = DBL_MAX;

using it like:

double v = Math<double>::MAX_VALUE;

It´s the only static dependency for my algebra template class...


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Carl Barron
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PostPosted: Sun Jun 11, 2006 12:48 am    Post subject: Re: templated constanst Reply with quote



In article <1149872688.630467.262110 (AT) h76g2000cwa (DOT) googlegroups.com>,
Javier Loureiro <derethorspam (AT) gmail (DOT) com> wrote:

Quote:
how can I write this template without a static member?

-- header --

template <typename Scalar
struct A
{
static Scalar MAX_VALUE;
};

-- explict instance --

A<float>::MAX_VALUE = FLT_MAX;
A<double>::MAX_VALUE = DBL_MAX;

using it like:

double v = Math<double>::MAX_VALUE;

It´s the only static dependency for my algebra template class...

static member functions ok?? they can be written and not require

separate initialization.

why not use std::numeric_limits<type> or its approach to provide
functions to provide the results as they are not compile time constants

template <class T> class A;

template <> class A<float> {static float max() {return FLT_MAX;}};
template <> class A<double> {static double max() const {return
DBL_MAX;}};
//etc.
// usage: double v = A<double>::max();

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Valentin Samko
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PostPosted: Sun Jun 11, 2006 12:49 am    Post subject: Re: templated constanst Reply with quote



Javier Loureiro wrote:
Quote:
how can I write this template without a static member?

You can't.
Quote:

-- header --
template <typename Scalar
struct A
{
static Scalar MAX_VALUE;
};
-- explict instance --

A<float>::MAX_VALUE = FLT_MAX;
A<double>::MAX_VALUE = DBL_MAX;

This is a common approach, such classes are usually called "traits".
In this particular case there is already one

#include <limits>
double max = std::numeric_limits<double>::max();

--

Valentin Samko - http://www.valentinsamko.com

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kanze
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PostPosted: Thu Jun 15, 2006 8:02 pm    Post subject: Re: templated constanst Reply with quote

Javier Loureiro wrote:
Quote:
I just read the "limits" header (included with visual 2003),
and it uses the macro :

#define _STCONS(ty, name, val) static const ty name = (ty)(val)

to declare numeric_limits member variables like has_infinity,
is_integer, etc, inside a struct declaration...

I wrote this simple code using such macro and the limits class
inheritance, and it does not compile...

#define MY_STCONS(ty, name, val) static const ty name = (ty)(val)

namespace mystd {

struct num_base
{
MY_STCONS(bool, is_bounded, false);
MY_STCONS(bool, is_exact, false);
};

template <class T
struct num_procs : public num_base
{
inline static foo() { return T(0); }
};

struct num_int_base : public num_base
{
MY_STCONS(bool, is_bounded, false);
MY_STCONS(bool, is_exact, false);
};

template <> struct num_procs<int> : public num_int_base
{
typedef int T;
inline static foo() { return T(20); }
};

What's the error message? I see an obvious error in the fact
that you don't declare a return type for the functions foo(),
but that error should be clear from the error message. The rest
seems OK at first glance.

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Conseils en informatique orientée objet/
Beratung in objektorientierter Datenverarbeitung
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