C++Talk.NET C++ language newsgroups   Archives   FAQ   Search   Memberlist   Usergroups   Register   Profile   Log in to check your private messages   Log in  Specifying a defualt value for the parameters in a method          C++Talk.NET Forum Index -> C++ language (comp.lang.c++) View previous topic :: View next topic   Author Message The Cool Giraffe Guest Posted: Sat May 12, 2007 9:10 am    Post subject: Specifying a defualt value for the parameters in a method I wonder if there's a simple way to specify the default values so that when i call a function designed to receive an int and a double, i can specify the first but not the latter. Something like: int foo (int i, double d) {...} but invoked by int a = foo (5); In Java that was done by simply overloading the methods and using a bunch of similar definition, calling each other. Is there a nicer solution? -- Vänligen Kerstin Viltersten (The Cool Giraffe) Back to top Guest Posted: Sat May 12, 2007 9:10 am    Post subject: Re: Specifying a defualt value for the parameters in a metho Hi, Quote: However, i wonder if one should do the "double d = 0.0" assignment in the header file, the cpp-file or perhaps both? Which would be recommended? Which is legal? It is better to declare it in the header file so that statements that use the default assignment in other translations units will compile. Cheers Back to top kingfox Guest Posted: Sat May 12, 2007 9:10 am    Post subject: Re: Specifying a defualt value for the parameters in a metho On 5月12æ—¥, 下å�ˆ3æ—¶41分, "The Cool Giraffe" <giraf...@viltersten.com> wrote: Quote: I wonder if there's a simple way to specify the default values so that when i call a function designed to receive an int and a double, i can specify the first but not the latter. Something like: int foo (int i, double d) {...} but invoked by int a = foo (5); In Java that was done by simply overloading the methods and using a bunch of similar definition, calling each other. Is there a nicer solution? -- Vänligen Kerstin Viltersten (The Cool Giraffe) int foo(int i, double d=0.0) { // ... } int a = foo(5); Back to top The Cool Giraffe Guest Posted: Sat May 12, 2007 9:11 am    Post subject: Re: Specifying a defualt value for the parameters in a metho kingfox wrote/skrev/kaita/popisal/schreibt : Quote: On 5?12?, ??3?41?, "The Cool Giraffe" giraf...@viltersten.com> wrote: I wonder if there's a simple way to specify the default values so that when i call a function designed to receive an int and a double, i can specify the first but not the latter. Something like: int foo (int i, double d) {...} but invoked by int a = foo (5); In Java that was done by simply overloading the methods and using a bunch of similar definition, calling each other. Is there a nicer solution? -- Vänligen Kerstin Viltersten (The Cool Giraffe) int foo(int i, double d=0.0) { // ... } int a = foo(5); Ah, that was really nice. Thanks. However, i wonder if one should do the "double d = 0.0" assignment in the header file, the cpp-file or perhaps both? Which would be recommended? Which is legal? -- Vänligen Kerstin Viltersten (The Cool Giraffe) Back to top        C++Talk.NET Forum Index -> C++ language (comp.lang.c++) All times are GMT Page 1 of 1 Powered by phpBB © 2001, 2006 phpBB Group