C++Talk.NET

Guest · Posted: Fri May 26, 2006 8:00 am Post subject: Sequence points.

Hello,
I was solving a C++ quiz that has the following question:

What is the outcome of running the following code:

int c=0;
cout<<c++<<c;

The answer says undefined. But in this case, isn't this statement
translated into:

cout.operator<<(c++).operator<<(c);

There should be a sequnce point before calling a funcion after
evaluation of the arguments. So shouldn't the incremented value of c be
stored before the call to first <<. If so it should be available for
the second <<, and the result would be 01.

Please help me with this confusion.

[ See http://www.gotw.ca/resources/clcm.htm for info about ]
[ comp.lang.c++.moderated. First time posters: Do this! ]