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Re: Must typename appear in template function's argument lis

 
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Kurt Krueckeberg
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PostPosted: Fri Jun 27, 2003 12:32 am    Post subject: Re: Must typename appear in template function's argument lis Reply with quote




Quote:
Hi, there,

I need to write a template function that the typename does not appear
in the argument list and the return value:

//=======
template<typename C> someClass;

template<typename T> int aFunct()
{
someClass<T> aClass;
// do something with aClass here
return 0;
}
//=======

Then the function is called by another function:
//========
...
int i = aFunct<float>();
...
//========

However, the function call line does not compile (in VC++). What is
the right way to do this?



template<typename T> int aFunct()

{

std::vector<T> v; // not used



return 10;

}



int x = aFunct<float>();




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Matthew Towler
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PostPosted: Sat Jun 28, 2003 12:46 pm    Post subject: Re: Must typename appear in template function's argument lis Reply with quote




Quote:
I need to write a template function that the typename does not appear
in the argument list and the return value:

However, the function call line does not compile (in VC++). What is
the right way to do this?


I am guessing you are using VC++6, in which there is a classic bug
which means such functions do not end up with different signatures
even when instantiated for multiple types, giving compilation failure.
The usual workaround is to add a dummy default parameter e.g.

template< typename T >
int foo( int, T* dummy = 0 )
{
(void)dummy); // this stops compiler warnings about the unused
parameter
}

foo<int>();
foo<MyType>()
now give different functions.

Matt

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