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qazmlp
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 Posted: Mon Apr 11, 2005 3:06 pm Post subject: Re: Format of compiler generated derived destructor when bas |
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Could anybody reply to this post? I would like to know what exactly
'C++ standard' mentions about this.
| Quote: | qazmlp1209 (AT) rediffmail (DOT) com (qazmlp) wrote in message
news:<db9bbf31.0504080226.71c45717 (AT) posting (DOT) google.com>...
I have a class like this:
class base
{
public:
virtual ~base() throw();
// Other members
};
Now, if I write a class like this:
class derived:public base
{
// Other members
};
What will/should be the format of the compiler-generated destructor for derived?
Will it be this:
- ~derived(); or
- virtual ~derived(); or
- virtual ~derived() throw();
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Alberto Barbati
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| Posted: Mon Apr 11, 2005 11:22 pm Post subject: Re: Format of compiler generated derived destructor when bas |
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qazmlp wrote:
| Quote: | Could anybody reply to this post? I would like to know what exactly
Will it be this:
- ~derived(); or
- virtual ~derived(); or
- virtual ~derived() throw();
|
It's "virtual ~derived() throw();" The relevant paragraphs are:
10.3/4 "Even though destructors are not inherited, a destructor in a
derived class overrides a base class destructor declared virtual; [...]"
(also notice footnote 97: "The use of the virtual specifier in the
declaration of an overriding function is legal but redundant (has empty
semantics).")
15.4/13 "An implicitly declared special member function (clause 12)
shall have an exception-specification. If f is an implicitly declared
[...] destructor, [...] f shall allow no exceptions if every function it
directly invokes allows no exceptions."
Alberto
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