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Daryle Walker
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 Posted: Fri Oct 31, 2003 2:59 am Post subject: Quick question on de-const-ing |
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I'm going to have a pointer to a const object (T const *), it's going to
be dereferenced in a read-only manner, but the interface function takes
a pointer to a non-const (U f(T *x)). I can use a const_cast without
any new worries, right?
There's another part of the library that could write through that
pointer. As long as my wrapping code blocks all the potential writing
calls, I have nothing to worry about, right?
(I've thought of evil hacks that can get around my blocks, which I
cannot counter-block. But I shouldn't let those bother me too much;
should I follow "protect against Murphy, not Machevelli"? I should have
less to worry about; the default implementations of the writing calls
just return error codes, I would have to do virtual overrides to
activate/add writing; so I just don't add those overrides. Now you can
see the evil hack, just subclass my leaf class and add the evil
write-activation overrides.)
--
Daryle Walker
Mac, Internet, and Video Game Junkie
dwalker07 AT snet DOT net
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Thomas Richter
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| Posted: Sat Nov 01, 2003 9:57 am Post subject: Re: Quick question on de-const-ing |
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Hi,
| Quote: | I'm going to have a pointer to a const object (T const *), it's going to
be dereferenced in a read-only manner, but the interface function takes
a pointer to a non-const (U f(T *x)). I can use a const_cast without
any new worries, right?
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Right. (Except maybe that you might want to change that interface. If
there is read-only access, then what's the point of not making it
const?)
| Quote: | There's another part of the library that could write through that
pointer. As long as my wrapping code blocks all the potential writing
calls, I have nothing to worry about, right?
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Right, but see above. What do you mean by "blocks all the potentional
writing"? You mean that you can ensure that the writings never take place
by apropriate side conditions, I assume?
So long,
Thomas
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