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Zongjun Qi
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 Posted: Fri Sep 22, 2006 12:04 am Post subject: Question about overloaded operator "*" of auto_ptr |
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In auto_ptr declaration, we can find auto_ptr overloaded the
"dereference" operator "*". Below is its signature:
T& operator*() {return *ptr;}
But my question is: since overloaded operators only expect to work with
a LEFT OPERAND of a instance of the class, then how can we use it in
our code like this:
auto_ptr<int> p<new int>;
....
*p = 8;
Instead, according to the overloaded operator usage syntax, we should
use it like this
p* = 8.
Well, aparantly "*p = 8" is the working way, after I tested on my linux
system. But why? ...
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Carlos Moreno
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| Posted: Fri Sep 22, 2006 5:10 am Post subject: Re: Question about overloaded operator "*" of auto_ptr |
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Zongjun Qi wrote:
| Quote: | In auto_ptr declaration, we can find auto_ptr overloaded the
"dereference" operator "*". Below is its signature:
T& operator*() {return *ptr;}
But my question is: since overloaded operators only expect to work with
a LEFT OPERAND of a instance of the class [...]
Instead, according to the overloaded operator usage syntax, we should
use it like this
p* = 8. [...]
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Seems like you have to hit the books a little -- go back to
your favourite C++ book's chapter on operator overloading, and
you should immediately understand why, after reading about the
rules of operator overloading (possibly in a section "Rules and
Limitations about operator overloading" in that chapter). (you
could also try a Google search for online tutorials -- I'm sure
you'llfind many)
Also, ask yourself the following: is that operator* a unary or
a binary operator? What about operator overloading for each of
these categories?
HTH,
Carlos
--
[ See http://www.gotw.ca/resources/clcm.htm for info about ]
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