C++Talk.NET

Andy Tompkins · Guest

I am having trouble understanding why line B will not compile. I understand
why line A and line C compiles since they have access to the i member. But
since D is derived from Base should it not have access to another Base
object's i member as well as access to it's own Base's i member?

class Base {
public:
Base() {}
virtual ~Base() {}
protected:
int i;
};
class D : public Base {
public:
void foo() {
int i1 = i; // line A

Base *b = new D();
int i2 = b->i; // line B, compile error, 'Base::i' :
cannot access protected member declared in class 'Base'

if (D *d = dynamic_cast<D*>(b)) {
int i3 = d->i; // line C
}
}
};

Thanks,
Andy.

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Francis Glassborow · Guest

In article <m%RJc.47549$Rf.45684@edtnps84>, Andy Tompkins
<atompkins (AT) georef (DOT) com.invalid> writes