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| Author |
Message |
Aff@n
Guest
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 Posted: Mon Aug 28, 2006 9:10 am Post subject: overloading operator [] |
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hi,
i wold like to ask, why is it when overloading operator[] we send int
value is there any way around?.
e.g.
class abc
{
protected:
int *a;
private:
int operator[](int );
};
int abc::operator[](int x)
{
int z;
z=a[x];
return z;
}; |
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Kai-Uwe Bux
Guest
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| Posted: Mon Aug 28, 2006 9:10 am Post subject: Re: overloading operator [] |
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Aff@n wrote:
| Quote: | hi,
i wold like to ask, why is it when overloading operator[] we send int
value is there any way around?.
e.g.
class abc
{
protected:
int *a;
private:
int operator[](int );
};
int abc::operator[](int x)
{
int z;
z=a[x];
return z;
};
|
In your case, operator[] takes an int argument because and only because you
defined it that way. You could as well do:
class abc
{
protected:
int *a;
private:
int operator[]( std::size_t );
};
int abc::operator[]( std::size_t x)
{
int z;
z=a[x];
return z;
};
Best
Kai-Uwe Bux |
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