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KublaPawn Guest
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Posted: Wed Jul 21, 2004 11:48 am Post subject: overloading enumerated types |
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Is it possible to overload an enumerated type.for example:
enum square{a1,b1,c1 ... f8,g8,h8};
and use a1++; to get from one square to another.
and a1+=8; to get to another row;
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Francis Glassborow Guest
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Posted: Wed Jul 21, 2004 7:11 pm Post subject: Re: overloading enumerated types |
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In article <0AhLc.19072$Gf7.669224 (AT) news20 (DOT) bellglobal.com>, KublaPawn
<KublaPawn (AT) netscape (DOT) net> writes
| Quote: | Is it possible to overload an enumerated type.for example:
enum square{a1,b1,c1 ... f8,g8,h8};
and use a1++; to get from one square to another.
and a1+=8; to get to another row;
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Yes. Whether it is desirable or a good design is an entirely different
issue.
Example:
square operator++(square val, int){
square temp(square(val+1));
if(temp == h temp = a1;
return temp;
}
I have made no attempt at polishing the above. I am just providing an
existence proof.
--
Francis Glassborow ACCU
Author of 'You Can Do It!' see http://www.spellen.org/youcandoit
For project ideas and contributions: http://www.spellen.org/youcandoit/projects
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Ulrich Eckhardt Guest
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Posted: Wed Jul 21, 2004 7:13 pm Post subject: Re: overloading enumerated types |
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KublaPawn wrote:
| Quote: | Is it possible to overload an enumerated type.for example:
enum square{a1,b1,c1 ... f8,g8,h8};
and use a1++; to get from one square to another.
and a1+=8; to get to another row;
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Yes, you can overload operators for enumerations.
No, the expressions 'a1++' and 'a1+=8' will never make sense, as 'a1' is a
constant. 'square s = a1; s++;' makes sense though.
Uli
--
FAQ: http://parashift.com/c++-faq-lite/
/* bittersweet C++ */
default: break;
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Victor Bazarov Guest
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Posted: Wed Jul 21, 2004 8:03 pm Post subject: Re: overloading enumerated types |
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KublaPawn wrote:
| Quote: | Is it possible to overload an enumerated type.for example:
enum square{a1,b1,c1 ... f8,g8,h8};
and use a1++; to get from one square to another.
and a1+=8; to get to another row;
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Yes, partially. The term is "overload some operators for an enumerated
type", not "overload an enumerated type".
You should be able to overload the post-increment, but not the compound
assignment.
square operator++(square& s, int) {
square r = s;
// here you define how to move from one to another
// and change 's' accordingly
return r;
}
The assignment operator has to be a member, and since enums are not
classes, they can't have members.
V
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