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[Newbie] Namespace and inheritance...

 
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Guest
PostPosted: Fri Jul 13, 2012 8:54 pm    Post subject: [Newbie] Namespace and inheritance... Reply with quote


Hello,

I am learning C++. I wrote the following C++ code to understand namespace and inheritance. It does not compile(g++ 4.6.3), but when I explicitly specify the scope resolution the program works. Why am I not able to directly call the public method implemented in the base class?


namespace N1 {
class C
{
public:
void F(const std::string& s)
{
std::cout << "N1::C::F(str): " << s.c_str() << std::endl;
}
};
};

namespace N2 {
class C : public N1::C
{
public:
void F(int i)
{
std::cout << "N2::C::F(int): " << i << std::endl;
}
};
};

int main()
{
N2::C c;
c.F(1);

// The following statement does not compile unless
// it is called with full scope resolution as follows:
// c.N1::C::F("one");

c.F("one");

return 0;
}

Thanks and regards,

Plug
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Victor Bazarov
Guest
PostPosted: Fri Jul 13, 2012 8:54 pm    Post subject: Re: [Newbie] Namespace and inheritance... Reply with quote


On 7/13/2012 4:54 PM, plug.gulp (AT) gmail (DOT) com wrote:
Quote:
Hello,

I am learning C++. I wrote the following C++ code to understand
namespace and inheritance. It does not compile(g++ 4.6.3), but when I
explicitly specify the scope resolution the program works. Why am I not
able to directly call the public method implemented in the base class?


namespace N1 {
class C
{
public:
void F(const std::string& s)
{
std::cout << "N1::C::F(str): " << s.c_str() << std::endl;
}
};
};

namespace N2 {
class C : public N1::C
{
public:
void F(int i)
{
std::cout << "N2::C::F(int): " << i << std::endl;
}
};
};

int main()
{
N2::C c;
c.F(1);

// The following statement does not compile unless
// it is called with full scope resolution as follows:
// c.N1::C::F("one");

c.F("one");

return 0;
}

This is covered by the FAQ. Please read FAQ before posting. You can
find the FAQ Lite here: http://www.parashift.com/c++-faq-lite/. Hint:
see section 23. And crank up the warning level on your compiler, maybe
you will get a useful diagnostic out of that tool for a change...

V
--
I do not respond to top-posted replies, please don't ask
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Bo Persson
Guest
PostPosted: Sat Jul 14, 2012 9:51 am    Post subject: Re: [Newbie] Namespace and inheritance... Reply with quote


plug.gulp (AT) gmail (DOT) com skrev 2012-07-13 22:54:
Quote:
Hello,

I am learning C++. I wrote the following C++ code to understand namespace and inheritance. It does not compile(g++ 4.6.3), but when I explicitly specify the scope resolution the program works. Why am I not able to directly call the public method implemented in the base class?


namespace N1 {
class C
{
public:
void F(const std::string& s)
{
std::cout << "N1::C::F(str): " << s.c_str() << std::endl;
}
};
};

namespace N2 {
class C : public N1::C
{
public:
void F(int i)
{
std::cout << "N2::C::F(int): " << i << std::endl;
}
};
};

int main()
{
N2::C c;
c.F(1);

// The following statement does not compile unless
// it is called with full scope resolution as follows:
// c.N1::C::F("one");

c.F("one");

return 0;
}


It has nothing to do with namespaces.

Declaring something named F in the derived class hides the name F from
any base classes. This is similar to declaring local variables in an
inner scope which hides names from outer scopes.

If you want to use the name anyway, you can either use the full name
(like you did), or add a "using N1::C::F;" to class C2.


Bo Persson
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Bo Persson
Guest
PostPosted: Sat Jul 14, 2012 9:55 am    Post subject: Re: [Newbie] Namespace and inheritance... Reply with quote
Bo Persson skrev 2012-07-14 13:51:
Quote:
plug.gulp (AT) gmail (DOT) com skrev 2012-07-13 22:54:
Hello,

I am learning C++. I wrote the following C++ code to understand
namespace and inheritance. It does not compile(g++ 4.6.3), but when I
explicitly specify the scope resolution the program works. Why am I
not able to directly call the public method implemented in the base
class?


namespace N1 {
class C
{
public:
void F(const std::string& s)
{
std::cout << "N1::C::F(str): " << s.c_str()
std::endl;
}
};
};

namespace N2 {
class C : public N1::C
{
public:
void F(int i)
{
std::cout << "N2::C::F(int): " << i << std::endl;
}
};
};

int main()
{
N2::C c;
c.F(1);

// The following statement does not compile unless
// it is called with full scope resolution as follows:
// c.N1::C::F("one");

c.F("one");

return 0;
}


It has nothing to do with namespaces.

Declaring something named F in the derived class hides the name F from
any base classes. This is similar to declaring local variables in an
inner scope which hides names from outer scopes.

If you want to use the name anyway, you can either use the full name
(like you did), or add a "using N1::C::F;" to class C2.

^^^^^^^^
Here "class C2" of course should be "class C in namespace N2".


Bo Persson
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Paul
Guest
PostPosted: Sat Jul 14, 2012 10:11 pm    Post subject: Re: [Newbie] Namespace and inheritance... Reply with quote
"Bo Persson" <bop (AT) gmb (DOT) dk> wrote in message
news:a6d4qaFkdrU1 (AT) mid (DOT) individual.net...
Quote:
plug.gulp (AT) gmail (DOT) com skrev 2012-07-13 22:54:
Hello,

I am learning C++. I wrote the following C++ code to understand namespace
and inheritance. It does not compile(g++ 4.6.3), but when I explicitly
specify the scope resolution the program works. Why am I not able to
directly call the public method implemented in the base class?


namespace N1 {
class C
{
public:
void F(const std::string& s)
{
std::cout << "N1::C::F(str): " << s.c_str()
std::endl;
}
};
};

namespace N2 {
class C : public N1::C
{
public:
void F(int i)
{
std::cout << "N2::C::F(int): " << i << std::endl;
}
};
};

int main()
{
N2::C c;
c.F(1);

// The following statement does not compile unless
// it is called with full scope resolution as follows:
// c.N1::C::F("one");

c.F("one");

return 0;
}


It has nothing to do with namespaces.

Declaring something named F in the derived class hides the name F from any
base classes. This is similar to declaring local variables in an inner
scope which hides names from outer scopes.

If you want to use the name anyway, you can either use the full name (like
you did), or add a "using N1::C::F;" to class C2.

Will that then hide the F in N2::C ?




--- Posted via news://freenews.netfront.net/ - Complaints to news (AT) netfront (DOT) net ---
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Jamie
Guest
PostPosted: Sun Jul 15, 2012 5:25 am    Post subject: Re: [Newbie] Namespace and inheritance... Reply with quote
What is "namespace"? What is a name? Do you know what a "name" is? You use
it like a weapon. So let it be written.

<plug.gulp (AT) gmail (DOT) com> wrote in message
news:b03e953c-31f1-4fc2-bb77-0fe79213d04f (AT) googlegroups (DOT) com...
Hello,

I am learning C++. I wrote the following C++ code to understand namespace
and inheritance. It does not compile(g++ 4.6.3), but when I explicitly
specify the scope resolution the program works. Why am I not able to
directly call the public method implemented in the base class?


namespace N1 {
class C
{
public:
void F(const std::string& s)
{
std::cout << "N1::C::F(str): " << s.c_str() << std::endl;
}
};
};

namespace N2 {
class C : public N1::C
{
public:
void F(int i)
{
std::cout << "N2::C::F(int): " << i << std::endl;
}
};
};

int main()
{
N2::C c;
c.F(1);

// The following statement does not compile unless
// it is called with full scope resolution as follows:
// c.N1::C::F("one");

c.F("one");

return 0;
}

Thanks and regards,

Plug
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