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merrittr · Guest

I am trying to build variables for a function using sprintf. However
they don't seem to be proper
char strings since submiting literals seems to work fine. Any advice
to get me rolling?

sprintf( i1, "%s %s \0",v1,v2 );
sprintf( i1, "%s %s \0",v3,v4 );
printf("answer %s\n",add(cTypeCurr,i1,i2));
printf("answer %s\n",add("i","3 i","4 i"));

here is the output I get:

---retval Ã¨Gâ™¥ Ã¨Gâ™¥
---0.000000 3 i 4 i

the function:

char *add(char *ctype, char *i, char *j)
{
double x,y,z,a;
static char retval[10]="retval";
printf("---%s %s %s\n",retval,i,j); <--output line
x=atof(i);
y=atof(j);
z=x+y;
sprintf( retval, "%f",z );
return retval;
}

Flash Gordon · Guest

merrittr wrote, On 21/05/07 07:43:

Jack Klein · Guest

On 20 May 2007 23:43:15 -0700, merrittr <merrittr (AT) gmail (DOT) com> wrote in
comp.lang.c:

merrittr · Guest

the v1,v2,v3,v4 vars ar built like this:

cVal=getchar();
while(cVal != '\n')
{
v1[iCharCount++] = tolower(cVal);
cVal=getchar();
}
v1[iCharCount++]='\0';
iCharCount=0;

typically vi v2 v3 v4 are "5 i" or "4.5 d"

cTypeCurr = "i" or "d" I don't think I will need this variable it is a
remnant of something I was trying.

whoops the second i1 should have been i2

I added the \0 after I was getting these results , sort of as a long
shot
to see if my string termination wasn't working. So sprintf null
terminates eh?

sprintf( i1, "%s %s \0",v1,v2 );
sprintf( i2, "%s %s \0",v3,v4 );
printf("answer %s\n",add(cTypeCurr,i1,i2));
printf("answer %s\n",add("i","3 i","4 i"));

here is the output I get:

---retval Ã¨Gâ™¥ Ã¨Gâ™¥
---0.000000 3 i 4 i