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loudking · Guest

Question: write a program which creates 5 processes (in addition to
itself). One of these processes must display 1, another must display
2
.... the last one displays 5. The parent process waits until all other
processes are finished, then returned.

My solution is that

/* Header files omitted */

#define NUMBER_PROCESS 5

void sig_chld(int sig)
{
pid_t pid;
int stat;

while ((pid = waitpid(-1, &stat, WNOHANG)) > 0)
{
;
}
signal(SIGCHLD, sig_chld);
}

int main(int argc, char *argv[])
{
pid_t pid = getpid();
int i;

signal(SIGCHLD, sig_chld);

for (i = 0; i < NUMBER_PROCESS && pid > 0; i++)
{
pid = fork();
if (pid < 0)
{
perror("Error fork");
exit(-1);
}
else if (pid == 0)
{
printf("%d\n", i+1);
}
}/* for i */

return 0;
}

Should I add a for loop outside the while loop in sig_chld function
to
make sure that exactly 5 child termination are captured?

Thanks!

Ian Collins · Guest

loudking wrote:

William Ahern · Guest

loudking <loudking (AT) gmail (DOT) com> wrote: