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PengYu.UT@gmail.com
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 Posted: Wed Oct 18, 2006 5:28 am Post subject: How to get the size of the array in boost::shared_array? |
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Hi,
I remember that the main difference between "int * a = new
std::complex<double>;" and "int *b = new std::complex<double>[10]" is
that the compiler keep the size of the array that "b" pointing to. So
"delete [] b" will call "std::complex<double>"'s destructor 10 times.
If that is the case, can we have any way to know the size of the array
the shared_array pointing to?
Thanks,
Peng |
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David Harmon
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| Posted: Wed Oct 18, 2006 7:32 am Post subject: Re: How to get the size of the array in boost::shared_array? |
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On 17 Oct 2006 17:28:40 -0700 in comp.lang.c++,
"PengYu.UT (AT) gmail (DOT) com" <PengYu.UT (AT) gmail (DOT) com> wrote,
| Quote: | If that is the case, can we have any way to know the size of the array
the shared_array pointing to?
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In general, you cannot get that information. Not any more than you
can for a naked pointer to a new[]'ed array.
If you need the size remembered for you, use the more general and
standard mechanism of std::vector<>. If you need shared management,
a boost::shared_pointer to the vector will do that for you. |
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