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forward declare member function so that it can be friend fun

 
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PostPosted: Thu Nov 09, 2006 10:11 am    Post subject: forward declare member function so that it can be friend fun Reply with quote



currently, i have a private function in cat named privateFun.

i would like to have this function "private" to all except dog's action
member function.

by using the following approach, all the dog's members can access all
the cat's private members.

// cat.h
//
#ifndef CAT_H
#define CAT_H

// forward declaration.
class dog;

class cat
{
private:
friend class dog;
void privateFun() {}
};

#endif
//
// cat.h

// dog.h
//
#ifndef DOG_H
#define DOG_H

#include "cat.h"

class dog
{
private:
void action()
{
cat c;
c.privateFun();
}
};

#endif
//
// dog.h

however, i would like to have ONLY dog's action member function to
access cat's private members.

i try the following approach but can't work.


// cat.h
//
#ifndef CAT_H
#define CAT_H

// forward declaration.
class dog;

class cat
{
private:
friend void dog::action(); /* HERE IS THE CHANGES AND COMPILATION
ERROR HAPPENS HERE. */
void privateFun() {}
};

#endif
//
// cat.h

// dog.h
//
#ifndef DOG_H
#define DOG_H

#include "cat.h"

class dog
{
private:
void action()
{
cat c;
c.privateFun();
}
};

#endif
//
// dog.h

Of course, i would get the following compilation error:

c:\Documents and Settings\YC Cheok\Desktop\aaa\cat.h(10): error C2027:
use of undefined type 'dog'

However, I just cann't include the dog header file into cat. This will
introduce circular include problem.

Any advice? Can I have something like member function forward
declaration? Thank you very much
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